For this problem, involving a weighted die, assume that the outcomes 1 through 4 are equally likely, that the outcomes 5 through 6 are equally likely, and that outcome 1 is 3 times as likely as outcome 5.(1) What probability should be assigned to rolling a 4?(2) What probability should be assigned to rolling a 6?

Answer:a.[tex]\frac{3}{14}[/tex]b.[tex]\frac{1}{14}[/tex]Step-by-step explanation:We are given that a die is rolled Let x bet the cases in favor of 5.Number of cases in favor of 6=xThen according to questionNumber of cases in favor of  1=3xNumber of cases in favor of 2=3xNumber of cases in favor of 3=3xNumber of cases in favor of 4=3xSum of total cases=[tex]x+x+3x+3x+3x+3x=14x[/tex]Probability of getting 5 =[tex]\frac{x}{14x}=\frac{1}{14}[/tex]Probability of getting 1=[tex]\frac{3x}{14x}=\frac{3}{14}[/tex]1.We have to find probability should be assigned to rolling a 4.The probability of getting =[tex]\frac{3}{14}[/tex]2.We have to find the probability of rolling 6.The probability of getting 6=[tex]\frac{1}{14}[/tex]