The length of a rectangle exceeds its width by 8 inches. The perimeter is 80 inches. Find the length and the width of the rectangle.

Answer:The width is 16 inches while the length is 24 inches.Step-by-step explanation:We are given that the length (L) is 8 more than it's width (W).The equation for this is: L=8+W.We are given the perimeter is 80. The equation for this is 2L+2W=80.Each term here is even so I'm going to divide both sides by 2: L+W=40.My system to solve is:L=8+WL+W=40I'm going to plug the first equation into the second giving me:(8+W)+W=40Drop the (), don't really need:8+W+W=40Combine like terms:8+2W=40Subtract 8 on both sides:     2W=32Divide both sides by 2:       W=32/2Simplify:      W=16So if W=16 and L=8+W then L=8+16=24.The width is 16 inches while the length is 24 inches.