Identify the lower class limits, upper class limits, class width, class midpoints, and class boundaries for the given frequency distribution. Also identify the number of individuals included in the summary. Blood Platelet Count of Males (1000 cells/muL) Frequency 0-99 3 100-199 54 200-299 76 300-399 21 400-499 0 500-599 0 600-699 1 Identify the lower class limits (in 1000 cells/muL).
Accepted Solution
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Answer:The lower limits (in 1000 cells/muL): 0,100, 200, 300, 400, 500, 600 .The upper limits (in 1000 cells/muL): 99, 199, 299, 399, 499, 599, 699.The class width(in 1000 cells/muL): 100.Class midpoints (in 1000 cells/muL): 49.5, 149.5, 249.5, 349.5, 449.5, 549.5, 649.5.Class boundaries (in 1000 cells/muL): -0.5, 99.5, 199.5, 299.5, 399.5, 499.5, 599.5, 699.5.Individuals included in the summary: 155.Step-by-step explanation:For the lower class limit is needed the smallest value in each class: 0,100, 200, 300, 400, 500, 600.For the upper-class limit is needed the biggest value in each class: 99, 199, 299, 399, 499, 599, 699.The class width is the difference between the lower limit of one class and the lower limit of the previous class. For example, 200 is the lower limit of one class and the lower limit of the previous class is 100, so 200-100=100.Class midpoints are the average of the limits of a class if the limits are 0 and 99 then:[tex]Midpoint=\frac{0+99}{2}=49.5[/tex][tex]Midpoint=\frac{100+199}{2}=149.5[/tex][tex]Midpoint=\frac{200+299}{2}=249.5[/tex][tex]Midpoint=\frac{300+399}{2}=349.5[/tex][tex]Midpoint=\frac{400+499}{2}=449.5[/tex][tex]Midpoint=\frac{500+599}{2}=549.5[/tex][tex]Midpoint=\frac{600+699}{2}=649.5[/tex]Class boundaries are the numbers than allow to separate each class, to find each one, first calculate the gap between each class (the lower limit of one class minus the upper limit of the previous one) and divide by 2:100-99=11/2=0.5Add this number to all the upper limit to find the upper boundaries: [tex]99+0.5=99.5[/tex][tex]199+0.5=199.5[/tex][tex]299+0.5=299.5[/tex][tex]399+0.5=399.5[/tex][tex]499+0.5=499.5[/tex][tex]599+0.5=599.5[/tex][tex]699+0.5=699.5[/tex]And subtract this number (0.5) from the lower limit to find the lower boundaries:[tex]0-0.5=-0.5[/tex][tex]100-0.5=99.5[/tex][tex]200-0.5=199.5[/tex][tex]300-0.5=299.5[/tex][tex]400-0.5=399.5[/tex][tex]500-0.5=499.5[/tex][tex]600-0.5=599.5[/tex]The total of individuals is equal to the sum of all the frequencies of each class:[tex]3+54+76+21+0+0+1= 155[/tex]