A can of tuna fish is a cylinder with a height of 1.75 inches and a diameter of 3 inches. If the can is half full, how many cubic inches of tuna is in the can?
Accepted Solution
A:
Answer: [tex]6.185in^3[/tex]Step-by-step explanation: The formula for calculate the volume of a cylinder is: [tex]V_{cylinder}=\pi r^2h[/tex] r is the radius of the cylinder and h is the height of the cylinder. Given the diameter of 3 inches, calculate the radius of the cylinder with: [tex]r=\frac{d}{2}[/tex] (Where d is the diameter) [tex]r=\frac{3in}{2}=1.5in[/tex] Knowing the height and the radius, you can calculate the volume of the entire can of tuna: [tex]V_{can}=\pi (1.5)^2(1.75in)=12.37in^3[/tex] As you want to know the cubic inches of tuna that are in the can (volume of tuna), and you know that the can is half full, then: [tex]V_{tuna}=\frac{V_{can}}{2}\\\\V_{tuna}=\frac{12.37in^3}{2}\\\\V_{tuna}=6.185in^3[/tex]